How can I sort odd numbers to come first followed by even numbers

Question

I want to sort in that, this input:[5,1,3,9,2,6,4,7,8] would result to:[1,3,5,7,9,2,4,6, 8] ::odds sorted, then followed by the evens. I code in python and Javascript, so I would prefer theuse of those two languages, but you can also give an answer in any other language.

Answer 1

🍬🍬🍬🍬
https://code.sololearn.com/WGo95FDvsa3f/?ref=app

Answer 2

I madr a simple code in Python:
https://code.sololearn.com/cRG5Zt1iZ3n3/?ref=app

Answer 3

I'm not a python programmer, but you can try a bubble sort, with different criteria this time around (i.e. if |number[n]| % 2 > |number[n + 1]| % 2 then swap them)

Answer 4

Python is my next goal... for now, with Ruby, I can suggest this (I am sure a Python or JavaScript solution would be quite similar):

nums = [5,1,3,9,2,6,4,7,8]
even_nums = nums.select { |x| (x % 2) == 0 }
odd_nums = nums.select { |x| (x % 2) != 0 }

sorted_nums = odd_nums.sort + even_nums.sort
print sorted_nums

(using modulo 2 to identify odds and evens, selecting on that criteria, recombining after sorting)