Code to get second largest among three .... considering d case dat 2 can b equal.....

Answer 1

let's suppose your numbers are a, b, and c.

int a, b, c;
int max1, max2;
max1 = max2 = -1;
if(a > max1) {
max2=max1;
max1=a;
}else if(a > max2) max2 = a;

if(b > max1) {
max2=max1;
max1=b;
}else if(b > max2) max2 = b;

if(c > max1) {
max2=max1;
max1=c;
}else if(c > max2) max2 = c;

The maximum values is max1 and the second largest is max2. Keep in mind max1 and max2 must have an initial value lower than all 3 numbers, here, i supposed all numbers are integers, greater than 0. Hopefully this helps

Answer 2

tysm