+ 1
What are the different ways of accepting input through the user in Java
2 Answers
+ 11
You can use any of the following ways based on the requirements.
⢠Scanner class
import java.util.Scanner;
Scanner scan = new Scanner(System.in);
String s = scan.next();
int i = scan.nextInt();
⢠BufferedReader and InputStreamReader classes
import java.io.BufferedReader;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s = br.readLine();
int i = Integer.parseInt(br.readLine());
⢠DataInputStream class
import java.io.DataInputStream;
DataInputStream dis = new DataInputStream(System.in);
int i = dis.readInt();
⢠The readLine method from the DataInputStream class has been deprecated. To get String value, you should use the previous solution with BufferedReader.
⢠Console class
import java.io.Console;
Console console = System.console();
String s = console.readLine();
int i = Integer.parseInt(console.readLine());
Apparently, this method does not work well in some IDEs.
+ 2
Could also use swing.
Such as JOptionPane.
import javax.swing.JOptionPane;
String input = JOptionPane.showInputDialog(null, "User Input");
*Won't work on CodePlayground*