Python: Simple calculator (WET to DRY)

Question

Hey guys, i'm wondering if you could help take a look at this code, is there anything i should do to make it more DRY?

while True:
print("Enter 'add' to add two numbers")
print("Enter 'subtract' to subtract two numbers")
user_input = input(": ")

x = (user_input != ("add" or "subtract"))
if x == True:
while x:
print("Try Again")
print("Enter 'add' to add two numbers")
print("Enter 'subtract' to subtract two numbers")
user_input = input(": ")

if user_input == "add":
break
if user_input == "subtract":
break

def add_subtract (y):
print("what numbers would you like to " + y +" ?")
num_1= int(float (input("first number: ")))
num_2= int(float (input("second number: ")))

if y == "add":
print("Your answer is: " + str(num_1 + num_2))

if y == "subtract":
print("Your answer is: " + str(num_1 - num_2))

add_subtract (user_input)

print("More numbers for me? Yes/No")
add_user_input = input(": ")

if add_user_input == "No":
break

if add_user_input == "Yes":
continue

if add_user_input != "No" and "Yes":
while True:
print ("Please insert a proper response")
print("More numbers for me? Yes/No")
add_user_input = input(": ")

if add_user_input == "No":
break

if add_user_input == "Yes":
break
if add_user_input == "Yes":
continue
else:
break

Answer 1

you may want to something like this

repeat = 0
while repeat == 0:
(whatever u want)
okay = int(input("u want using this calculator again? "))

okay = repeat

and never give up to coding.its like a apollo rocket launch.slow at earth, but when reach space it will so fast. TRY HARDER!!!