Please explain this question???

Question

#include <iostream>
using namespace std;

int main() {
int x=17;
cout << (x>>2);
}

why the output is 4???

Answer 1

Doing x>>2 is the same as doing x/(2^2) so 17/4 is 4

It is a binary shift to the right :
17 = 1*16 + 0*8 + 0*4 + 0*2 + 1*1
= 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 1*2^0
=(10001)2
Now, we shift the bits to the right and we obtain
17>>2 = 100|01
the part on the right of | is just ignored and we keep only 100
(100)2 = 2^2 + 0*2^1 + 0*2^0
= 4

Answer 2

A resource for it

http://www.cprogramming.com/tutorial/bitwise_operators.html

Answer 3

the output is 68

"x << 2" is a bit wise operation

=
2^2 = 4

Answer 4

thanku baptiste

Answer 5

You are welcomed :)