Need a small clarification on the following code in the description...

Question

if 1 == 3:
print ("1")
elif 1 == 3 and 5:
print ("2")
elif 1 == 4 or 1 == 7:
print ("3")
elif 1 == 3 or 2:
print ("3a")
elif 1 == 1:
print ("4")
else :
print ("5")

# Why is my output ==> 3a instead of ==> 4 ? Why is the condition [ 1 == 3 or 2 ] True as I think it means if 1 is equal to either 2 or 3 or both ( and this should be False)

Answer 1

it evaluated the whole expression as true because of the second part: or 2

this interprets as: is 2 a truthy value ? which is true

what you should do is write it as follows:
elif 1== 3 or 1 == 2

Answer 2

also the expression and 5 translates to: and 5 is a truthy value? which is also true .. but the whole expression successfully translated to false because of the first part: 1 == 3