Can some one explain this code

Question

public class Program
{
public static void main(String[] args) {
boolean b=false;
if(b=false)
System.out.println("1");
else if(b)
System.out.println("2");
else if(!b)
System.out.println("3");
else
System.out.println("4");
}
}

Answer 1

if the 1st if statement was
if(b==false)
then that has been executed
and the ans has been 1 (e)
cause b==false

== means checking if the value is same or not
= means assigning a value

Answer 2

are you sure you copied it as it is?
b=false check this

Answer 3

thanks nw I understand

Answer 4

yes it's a objective question here are the options

a) fail to compile
b)2
c)no output
d)4
e)1
f)3
g)runtime error

Answer 5

ans is 3
i mean f

Answer 6

b=false
means b is false now..
so if(b)--> if(false)
no execution
else if(b)--> else if(false)
no execution
else if(!b)--> else if(not b)--> else if (not false)--> else if(true)
executes
else part dont execute..

if(True)//if(not False)//if(8)//if(7==7)
this things always ececutes