why "else" not executed?

Question

def f():
my code
choose=input("you want to play again? y or n ?")
if choose == 'y' or 'Y' :
return f()
else :
exit()
f()

when I input letter not y or Y, The program still executed,please tell me why? thx !!

Answer 1

maybe you can try to do these modifications

def f():
choose=input("you want to play again? y or n ?")
if (choose == 'y') or (choose =='Y'):
return f()
else:
print('bye')
exit()
f()

Answer 2

thank you for answer!! solved my problem , but I don't understand why do I input any letter in my code, The result always return f()?