What is the output of this code and why?

Question

int x = 4;
int y = ++x * 4 / x + x;
System.out.print(y + x);
Please anyone help me to shortout the problem.
Thanks in advance!!!☺

Answer 1

++x=5 //incrementation of x by 1, x=x+1=>4+1=5
now, x=5 //x becomes 5 due to incrementation
++x*4/x=>5*4/5=4
y=++x*4/x+x
=4+5
=9
Now, y=9 and x=5
So, output will be 9+5= 14

The incremented value of x is used in place of x...
So output you'll get is 14...

Answer 2

According to diagnostics, the value of y is 9. The prefix increment statement is evaluated prior to statement evaluation, hence all x in the y assignment statement is 5.

y = 5 * 4 / 5 + 5
y = 9

Final output prints (x + y), which is (5 + 9) = 14.

Answer 3

@Tanjibur Because ++x increments x by 1 and store it back to x.

Answer 4

++x increments value by 1 and uses it.
x++ uses it and increments value by 1.

Answer 5

@vengat

...
if this continued then it will become question of the day 😂😂😂

Answer 6

@Tanjibur I made a careless mistake, using the non ++ed value of x.
Answer now edited. Thanks for pointing it out

Answer 7

You made me do my first java code too!
TBH I suck at Java

Answer 8

sounds like your homework hahahaa
int x=4
int y=(++x=5)*4/(5)+5
y=9
x+y=5+9=14
Why not you try on code playground?

Answer 9

https://code.sololearn.com/cnQ1460xStRV/?ref=app

Answer 10

@Tanjibur Rahman

++ is an increment operator, it increments a value by 1. The increment/decrement operators can be applied before (prefix) or after (postfix) the operand. The only difference is that the prefix version (++x) evaluates to the incremented value, whereas the postfix version (x++) evaluates to the original value.

Answer 11

My advice would be to do some reading on operator precedence in Java (read the official Oracle documentation and play with code). Operators with higher precedence are evaluated before operators with relatively lower precedence.

The unary (prefix) operator has higher precedence than multiplicative operators, which in turn have higher precedence than additive operators.

That means ++x gets evaluated first. So y = 5 * 4 / 5 + 5

x is now 5 and y is 9 and your code outputs 14 ☺️

Answer 12

++x just works like that. Can't say anything more.
Javascript PHP, C++,C# all use these incrementers

Answer 13

Please people
I would like to end this discussion.
Answer is settled.
So is explanation.
----------CLOSE THIS QUESTION-------------

Answer 14

u got y=5 *4/5 +5
☝☝☝

what will u do here( 5*4 then divide by 5 ) = 4 or (5 * 4 divide by 5) =0

this is ur main doubt ,

then buddy just see 👉precedence order👈 for doing these question

Answer 15

Here ++ used before x is a prefix increment operator. It first increments the value of x by 1and then further calculation goes on.
Therefore:-
y = 5*4/5+5;
(y= 4+5=9)
Now x+y = 9+5 = 14

Answer 16

ans is also 14.
++x++4=5
y=9
x+y=5+9=14

x is increment

Answer 17

guys guys guys
he knows the solution now
no need to answer

Answer 18

output is 14....
points that u need to remember is that
1)value gets incremented from right to left
2)During arithmetic operations Priority order of the application operators follow the rule of BODMAS
3)And of course when u are addin' up x & y for the output don't forget tp take the incremented valure of x which is 5

Answer 19

Tnxx Daniel Stanciu ☺
Now I get it

Answer 20

I got the result as 14 according to my calculation,
and i think lot many explanations are already given before i saw the question.