int x=168; int y=60; int z; z=x&y; What will be the value / output of z??

Answer 1

bitwise AND (when both digits are 1)
10101000 = 128+0+32+0+8+0+0+0 = 168
00111010 = 0+0+32+16+8+0+2+0 = 60
00101000 = 0+0+32+0+8+0+0+0 = 40

Answer 2

how did you do it?

Answer 3

thanks

Answer 4

40