How to store integer number 12345 in character array

Answer 1

http://www.cplusplus.com/reference/cstdlib/itoa/

If your compiler doesn't support this, you can use the good ol' stringstream method.

#include <iostream>
#include <sstream>

int main()
{
std::stringstream obj;
std::string str;
int num = 12345;

obj << number;
// push number into string stream

obj >> str;
// push stream content to string variable

std::cout << str;
// now you have a string which can be used like a char array
}

Answer 2

why to store a integer in character?

Answer 3

And as a smaller way, In C++11 we have 'to_string()' for the same :

string no = to_string(12345);
cout<<no;

// We even have itoa() in C++ 11 for the string class...