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result[j++] = (char)((int)c[0]^32). How to do work this code?Someone explain me.Pls,I'm confuse.

public void abbre() { char[] c, result; int j = 0; c = new char[str.Length]; result = new char[str.Length]; c = str.ToCharArray(); result[j++] = (char)((int)c[0] ^ 32);

6th Sep 2017, 12:11 PM
Lin N
Lin N - avatar
1 Answer