What is the output of this code? Why is the output 2?

Question

int x=0;
for(int z=0; z<5; z++){
if((z>2)&&(++x>2)){
x+=7;
}
}
System.out.print(x);

Answer 1

//loop 1 , z=0... 1st condition ie z>2 becomes false ... so not checked for ++x >2 ... bcz for && if one condition goes false then whole will be false

// loop2 , z=1,x=0,

//loop3 , z=2,x=0,

//loop4, z=3 .... 1st condition ie z>2 becomes true ... not it checks 2nd condition .. ie. ++x >2 .. which comes false ... so x+=7 is not executed ... but value of x gets increased by 1
3rd loop , z=3,x=1

//lool5 , z=4 ... x=2 .... again both conditions are checked but since 2nd condition again comed false thats why x+=7; not gets executed

hope u like the explanation and got what i want to say ☺

Answer 2

Because z can be greater than 2 just for 2 times in the loop. From when z is greater than 2, it checks next condition and the value of x increases. It's simple.

Answer 3

Thanks to all. I was confused because I didn't know to break statement IF in the first condition
P.S. I'm sorry with my English. :)

Answer 4

Here is the reason .After 2 loops,z =3,at this time x=1,the next loop,z=4,++x =>x = x+1=2,then next loop;z =5, loop end,x=2;the 2nd case(++x>2)never satisfied.