Hiding unselected array elements? - Java

Question

Hi guys!. Currently I am using a 2 dimensional array with elements ranging from A1, A2, A3... to C3. When the user inputs a value (eg; A1) the program goes through the array to find a match. If the user's input matches one of the array elements then it will override that input with an x (to indicate a miss). However, the issue is, I would like my program to display the grids as so once the user has missed, for example:

[x][ ][ ]
[ ][ ][ ]
[ ][ ][ ]

rather than

[x][A2][A3]
[B1][B2][B3]
[C1][C2][C3]

I was wondering whether there was a way to take the user's input and only display the x along with the empty cells; Perhaps we can output the array normally but somehow hide/exclude the other elements that have not been selected by the user, thus only displaying x's and empty cells?

https://code.sololearn.com/chk1UmVfA874/#java

Answer 1

Not sure if I got your question... but I'll give it a try:

The easy way:
enhanced for loop like:
for (String s : myArray) {
if (s.equals ("x") )
// print [x]
else
// print [ ]
}

Another way:
Create your own class / type for the elements of the array with two attributes: the initial String and a bool for the right guess. Override toString of your type and check the bool attribute to return x or empty.

Answer 2

Sry, for a two dimensional array you need to nest two loops, like:
for (String s[] : array) {
for (String t : s) {
if(t.equals("x"))
System.out.println("[x]");
else
System.out.println("[ ]");
}
}

Answer 3

Hi, thanks for responding. I tried implementing the loop but it appears I keep getting incompatible type from: for(String s: array)
Any ideas?: https://code.sololearn.com/chk1UmVfA874/#java