Why is the output 0 2 2 4 4 for this for loop?

Question

for (int = 0; i < 6 ; i ++){
System.out.println(i);
System.out.println(i++);
}

Answer 1

I'm guessing that this is just a typo, but i is not assigned in the initialization section of your for loop. Once that is fixed and the for loop is ran the output should be:
0
0
2
2
4
4
not 0 2 2 4 4

I'm also going to guess that your problem is the understanding of i++ and what is happening with:
System.out.println(i++);
i++ (postfix) will use the current value of the variable i and then increment the value.
So i is output, then incremented, then i is incremented once again in the incrementation section of the for loop.

If the prefix incrementation (++i) were used instead then the value of i would be incremented first and then output. resulting in:
0
1
2
3
4
5

Answer 2

Thank you so much for the explanation. I get it now! And sorry you had to navigate through the various mistakes I made in posting the question