i tried compiling my source code in visual studio 2017 , it compiles without errors , but doesn't work

Question

it is a program to print armstrong numbers below a certain limit , ie addition of cube of each digit in number must be equal to the number ie , 153 where 1*1*1 + 5*5*5+3*3*3 = 153

here is my source code i tried compiling

#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>

#define _CRT_SECURE_NO_WARNINGS

int i, a, b, c;

char d[12];
char e[12];

int main(int argc, char const *argv[])
{
for (i = 0; i < 1000; i++)
{

if (i<9)
{
printf("\n");
}

if (i > 10 && i >= 99)
{
_itoa_s(i, d, 12);
// sprintf (i,"%d",d);

b = d[0] * d[0] * d[0] + d[1] * d[1] * d[1];

if (b == i)
{
printf("%d", i);
}

}

if (i>99 && i<999)
{
_itoa_s(i, e, 12);
//sprintf (i,"%d",d);

b = d[0] * d[0] * d[0] + d[1] * d[1] * d[1] + d[2] * d[2] * d[2];

if (b == i)
{
printf("%d", i);
}
}

if (i <= 999)
{
break;
}
}
return 0;
}

Answer 1

If there's no syntax errors then there may be logical errors.

Example (Errors (Javascript)):

//Syntax error

var num # 5;
alert(num);

-the syntax error is that # should be =

//Logical error

var num = 5;
/*alert(num);*/

-this is a logical error because it will compile with no syntax errors but will produce nothing because the alert function is commented out

Answer 2

You're trying to calculate the ASCII of d, instead of the actual number. You need to convert each digit of d.

For example you would do:

int digit1 = d[0] - '0';
int digit2 = d[1] - '0';

then calculate

b = digit1*digit1*digit1 + digit2*digit2*digit2;