Question from versus

Question

int k;
do
{
k++;
}
while (k<0);
writeline(k);

do-while loop has at least 1 iteration. Thus output of the code is 1?

Answer 1

@Tony I asked, because it is the wrong answer in versus :/

Answer 2

of course LOL...

first run K = 0 + 1
on checking IF K LESS THAN 0 for loop back.

it never loop back because K already higher than 0.

Answer 3

scenario :
k started with 0
k entered do loop
k received ++ ( k becomes 0 + 1 = 1 )
k goes to checking
is K ( 1 ) Lower than 0 ? Nope , then it out the loop.
if only K is lower than 0 , it stay inside the loop.

but , regardless how many times the loop is ,
write line only occur 1 times , at the very least of the code ,
which is the very last result of k to be written , and it's 1.

so , yes , output is : 1.