Solve the expression 100%20-5*7>1&&0||6

Question

in C language can anyone find the solution plzz

Answer 1

Look at this page on order of precedence in C:

http://en.cppreference.com/w/c/language/operator_precedence

So firstly you do 100 % 20 which is 0:
0 - 5*7 > 1&&0||6,

then 5*7 is 37 and 0 - 35 is - 35:
-35 > 1&&0||6,

after that - 35 > 1 gives out "false" which has a numeric value of 0:
0&&0||6,

next 0&&0 is false&&false which is again false:
0||6,

and finally the "or" operator is true if one value is true, 0 is false and any value other than 0, false, undefined, etc. is truey, truey or false is true and the numeric value of true is 1 so that is the answer.