How to call static member functions?

Question

static member called direct no need to create object

Answer 1

you answered your own question 😋

static void msg(){System.out.println("hello");}

main

msg();

output hello

Answer 2

@Bagshot i found this

You do need to create instances, because a random-number generator has state. Specifically, state that controls the current position in the pseudo-random sequence.

If you want multiple independent generators (that don't share state), then you need separate instances.

Answer 3

@Bagshot i didnt know that, i have used Random a few times and have always created and instance maby becuase its part of package util?

Answer 4

static member call directly

Answer 5

What about Random? It's apparently static, yet every example I see uses an instance. Strange.

Answer 6

@David, it confuses me as well. Can't find a decent explanation, either.

Answer 7

because static member called automatically and once

Answer 8

@David: thanks, mate, that kind of makes sense now.

@Gordie: I'm doing a software development course and one of the questions asked me to select static classes from a list. The correct answers were Random and Math. It left me a little confused as I did not think Random was static, but apparently so.