Please i need easy and appropriate explanation to this code.

Question

def recur(0):
if n==0
return 0
else:
return n + recur (n-1)
print(recur(3))

how comes answer is 6?? 😟

Answer 1

oh, I see... thanks 👍

Answer 2

when you print recur (3), what goes through is: n is not equal to 0, thus n = 3 + recur (2) + recur (1) which equals 6.

That's because recur calls itself, adding the sum of its number minus 1 (3 + 2 + 1) and exits only when recur gets to 0