Pattern challenge : Enter 5 numbers if the largest is bigger than the sum of the two smallest number then print a triangle else

Question

-else print an inverted triangle.
the number in triangle is largest one
if you've a duplicated numbers u use them unless all are the same.in this case print a flat line 😃.
Input: 12345
Output:
5
55
555
5555
55555
Input:37691
Output:
9
99
999
9999
99999
999999
9999999
99999999
999999999
Input:34563
Output:
666666
66666
6666
666
66
6
Input:67548
Output:
88888888
8888888
888888
88888
8888
888
88
8
You can use your numbers .

Answer 1

My try:
https://code.sololearn.com/Wicy8ZLVFjdi/?ref=app

Answer 2

Could you please clarify the case for duplicate numbers?

Beisdes that, the number in triangle would always be the largest number except the orientation. Am I right?

Answer 3

@ChaoticDawg I see, maybe it's just me confused with the requirements. I've done in the folowing way:

s1 + s2 = largest ( Flat line )
s1 + s2 < largest ( Normal triangle )
s1 + s2 > largest ( Inverrted triangle )

Let's wait for the confirmation from the OP.

Answer 4

Just my opinion, how about printing a flat line if both numbers are equal?

Answer 5

Here's my C# implementation! ✌

LINQ One-Liner〰
Enumerable.Range(1, digit - 1)
.Select(n => (
isInverted ?
n * (2 * digit - n + 1) / 2 :
n * (n + 1) / 2) +
2 * (n - 1))
.ToList()
.ForEach(i => str = str.Insert(i, "\n"));

I doubt this is not the recommended way to solve the challenge as I've abused LINQ with side-effect this time. This solution relies on formula for inserting new line into the string to form the triangle since the number occurences are the same for all 3 cases. Enjoy~ ❤

https://code.sololearn.com/c9R26iY77gdF/?ref=app

Answer 6

I'm almost done now. Can I confirm the output for 34563? Isn't it a straight line since 3 + 3 = 6?

Answer 7

nums = list(input("Input 5 digit number: ")).sort()
print()

high, low1, low2 = int(nums[-1]), int(nums[0]), int(nums[1])

if high == low1:
[print(high, end='') for _ in range(high)]
elif (low1 + low2) >= high:
for i in range(high):
[print(high, end='') for _ in range(high-i)]
print()
else:
for i in range(high):
[print(high, end='') for _ in range(i)]
print()

Answer 8

@Zephyr I read it as if all the values are equal then print them on a line. So if the smallest number is the same as the largest.

For 34563 the example shows it to be an inverted triangle. So if the 2 smallest numbers are equal to or greater than, then print it as an inverted triangle.

Answer 9

@zephyr
s1+s2 < largest (normal triangle)
s1+s2 >= largest (inverted triangle)
n1=n2=n3=n4=n5 (flat line )

Answer 10

edited

Answer 11

👍👌