Is it possible in python, that for example 3.8-3 is 0.8000000000.... or with any other integer?

Answer 1

Without writing your own class and overriding the operation magic methods (assumedly to do it in strings), there's "import mpmath"
http://mpmath.org

because...here's 0.8 natively in straight Python:

print("{:.52f}".format(0.8))
0.8000000000000000444089209850062616169442667236328125

Answer 2

Oh I meant float* not integer

Answer 3

I want that:
Input:
x=3.8
z=x-int (x)

Output: 0.8

Answer 4

print (z)***

Answer 5

what exactly u wantt

Answer 6

its floting point precision..
ans will be like that
0.799999999998