[SOLVED] Why is 16 not printed in this code when breaking is only when i == 32?

Question

Tried while loop with two if statements . original value of i = 1. then i = i*2. to continue till i <= 10, then breaking at i = 32. result was 2, 4, 8, breaking, finished.

Answer 1

If you are referring to the code below:
https://code.sololearn.com/cdhCygSbUI6H/?ref=app

It only prints when i < 10, so the last is 8
When it reaches 16 it does not meet the first condition (as 16 > 10) and goes without doing anything, back to the beginning of the loop. Then it gets doubled to 32 and breaks. Anything that stands after the break statement cannot be executed.

Answer 2

Thanks a lot Kuba for the explanstion. now it's clear.

Answer 3

can you share or copy the code maybe ? wild guess is that you continue or dont print anything after i <= 10