How to use switch to compare percentages..

Question

the program is like this: user need to input his percentage . the program should be like thi
case 1
>=80 //formula used
cout<<D

case 2
>=60&&<80 // formula used
cout<<FD

etc...
is it possible to use switch statement.?.I need to use switch not if else..

Answer 1

@xxxfacepunchxxx

#include <iostream>
using namespace std;

int main() {

cout << "Are your older 18? Y / N" << endl;
char var;
cin >> var;

switch(var){
case 'y':
case 'Y':
cout << "come in!";
break;
case 'n':
case 'N':
cout << "too young!";
break;
default:
cout << "your answer isnt clear!";
break;
}

return 0;
}

Answer 2

Hi everyone!
i have the same problem:
how to realise case 'y'||'Y' ?

#include <iostream>
using namespace std;

int main() {

cout << "Are your older 18? Y / N" << endl;
char var;
cin >> var;

switch(var){
case 'y'||'Y':
cout << "come in!";
break;
case 'n'||'N':
cout << "too young!";
break;
default:
cout << "your answer isnt clear!";
break;
}

return 0;
}

Answer 3

int x=80;
switch(x)
{
case 80 ... 90: cout << "wgfhh";
break;
case 10 ... 20: cout << "hjgfy";
break;
}

you can use range or value not >= like conditions, what you are asking is not standard GCC complier work.

Answer 4

you are asking me?