code that will count the number ?

Question

#like this but only one while
count = 0
while count < 11 :
print(count)
count = count + 1
else:
count = 10
while count > 0 :
print(count)
count = count - 1

Answer 1

You no need for else:

count = 0
while count < 11 :
print(count)
count = count + 1

count = 10
while count > 0 :
print(count)
count = count - 1

Answer 2

Not really know what you mean here...

Answer 3

don't understand your point?

Answer 4

If you mean a code to reverse the number, here is one:

def print_reversed(n):
if n > 0:
print((n % 10), end='')
print_reversed(int(n / 10))

print_reversed(543210)

Answer 5

#i wrote it but not so good

count = 0
while count < 11 :
print(count)
count = count + 1
else:
count = 10
while count > 0 :
print(count)
count = count - 1