What's wrong with this code??

Question

what I am trying to achieve is that the program salute you.

#include <iostream>

using namespace std;

int main()

{

int name;
int last;

cout<<"Write your first and lastname"<<endl;
cin>>name>>last;

cout<<"its a pleassure Mr"<<endl;
cout<<name<<last<<endl;

return 0;
}

WHAT'S WRONG WITH IT???

Answer 1

You are inputting name use a string(array of characters).
#include <iostream>

using namespace std;

int main()
{

char name[20],last[20];

cout<<"Write your first and lastname"<<endl;
cin>>name>>last;

cout<<"its a pleassure Mr"<<endl;
cout<<name<<last<<endl;

return 0;
}

Answer 2

int means integer. int can only store numbers from -32767 to 32768.
char stores one alphabet or any other characters even tab spaces,new lines etc.
If we write

char a;
then it can store one character only.

char name[20];
this means I declared a variable that is named 'name' and can store up to 19 characters. That is I allocated it memory equal to 20 bytes.

Answer 3

use array of char for holding character values , they wont store in int u need string

Answer 4

int?

Answer 5

use char*name or string name datatype.
string data type works on latest compiler only

Answer 6

actually the problem comes once I feed my info

it does not act the way its suppose to be.

instead of greeting it outputs

"it's a pleasure Mr. 01"

Answer 7

so if I'm right what Mr.Megatron means is that integer does not work for things more complex than numbers right? in order to input more characters we use "char"? I also see that you wrote [20] that means that the length of the input can be no longer than 20 characters right?

what does "char" means??

Thank you folks.