why won't it work? :( why won't the if and while function accept my in statement

Question

"""try to make it repeat!"""
repeat = ['y','yes']
"""Imports here"""
from math import pi
"""Calculator"""
#Definitions
def add(x,y):
return x+y
def sub(x,y):
return x-y
def div(x,y):
return x/y
def mul(x,y):
return x*y
def square(x):
return x**2
def SquareRoot(x):
return x**(1/2)
"""Dictionaries"""
#Warning:Extremely messy!
division = ["Division","Divide","/","div"]
multiplication = ["*","x","times","multiply","multiplication","multiple"]
subtraction = ["-",'minus','subtract','subtraction']
addition = ['+','plus','addition','add']
root = ['root','squareroot','square root']
square = ['square','squared','power 2']

#Code
while repeat in repeat:
choice = input("Input type of operation!(+,-,*,/,^2,^1/2)")
if choice in division or multiplication or subtraction or addition:
num1 = int(input("ENTER FIRST NUMBER"))
num2 = int(input("ENTER SECOND NUMBER"))
if choice in addition:
print(num1,"+",num2,"=",(num1+num2))
elif choice in subtraction:
print(num1,"-",num2,"=",(num1-num2))
elif choice in division:
print(num1,"/",num2,"=",(num1/num2))
elif choice in multiplication:
print(num1,"*",num2,"=",(num1*num2))
elif choice in root:
num3 = int(input("ENTER A NUMBER"))
if choice in square:
print(num3,"^2","=",(num3**2))
elif choice in root:
print(num3,"^(1/2)","=",(num3**(1/2)))
else:
print("continue")
else:
print("something went wrong!", print(pi))
repeat = input("Do you want to perform another calcualtion?(Y/N)")

Answer 1

Your 'repeat' var is not assigned a value when the while loop runs. Have you tried 'while True', then if user enters repeat = 'N' , you can simply 'break' out of the loop.