Q&A Discussions
hey guys, I've been trying to work out the formula 'v=I*r'. But whenever I run the program and input values for I and r, it doesn't give the right answer.
This is the code
#include <iostream>
using namespace std;
int main() {
int i,r;
int v = i*r;
cout<<"what is the value of i?\n";
cin>>i;
cout<<"what is the value of r?\n";
cin>>r;
cout<<"voltage ="<<v<<endl;
return 0;
}
p/s: I'm new to programming
1 Vote
8 Answers#include <iostream>
using namespace std;
int sum(int a, int b=42) {
int result = a + b;
return (result);
}
int main() {
int x = 24;
int y = 36;
//calling the function with both parameters
int result = sum(x, y);
cout << result << endl;
//calling the function without b
result = sum(x);
cout << result << endl;
return 0;
}
why is da last function cout 66 and not 48 isn't it suppose to add 24+24?
1 Vote
6 Answersusing System;
namespace GoodProgrammerTest
{
class Program
{
static void Main(string[] args)
{
Console.Write("Enter Yes or No");
Console.Write(
"Do you programme every day? : ") ;
int answer = Console.ReadLine();
if (answer =="Yes")
{
Console.WriteLine(
"You will be a good programmer");
}
else
{
Console.WriteLine(
"You will not be a good programmer");
}
}
}
}
2 Votes
3 Answerscan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Votes
3 Answerswhat will be output??
#include <iostream>
using namespace std;
int main(int a)
{
cout << a << "\n";
return 0;
}
int main(char *a)
{
cout << a << endl;
return 0;
}
int main(int a, int b)
{
cout << a << " " << b;
return 0;
}
int main()
{
main(3);
main("Subodh");
main(9, 6);
return 0;
}
if output is compilation compilation error then how can we overload "main" function in C++
0 Votes
5 AnswersWhile prototyping friend functions in a class is it necessary to always pass the address of the object as parameter?If so why is it that we have to pass address as parameter..In programs involving compositions we never used addresses...Why is the need for address of the objects while using friend?
4 Votes
1 Answer
what have i to do, if i want that the program always writes for example :
0+1
1+2
3+3
6+4
10+5
15+6
...
because now it just writes
1
3
6
10
15
...
and maybe if it works, can i make then
0+1=1
1+2=3
3+3=6
6+4=10
#include <iostream>
using namespace std;
int main(){
int i;
int sum = 0;
for (i = 1; i <= 100; i++){
sum = sum+i;
cout<<sum<<endl;
}
cout<<sum;
return 0;
}
1 Vote
5 Answersif i text 21 it stacks. program says you are a child. you are a teenager. you are adult. how can i delete this "stack".
#include <iostream>
using namespace std;
int main() {
int age;
cin>>age;
if (age>=14){
cout<<"You're a Teenager"<<endl;
}
if (age>=18){
cout<<"You're adult"<<endl;
}
if (age>=0){
cout<<"You're a Child"<<endl;
}
else{
cout<<"Are u stupid ?"<<endl;
}
return 0;
}
0 Votes
4 Answers
so although using srand(time(0)) can be used to get truly random numbers, how truly random are they? For example, if one were to call this method at the same time (in this example, if one were to use this command at 51s) each time would the numbers generated be the same???
If so, are the numbers still truly random??
And if this theory is true, how can one generate truly random numbers that cannot repeat based on external variables (e.g., time)?
2 Votes
4 Answersguys this code I wrote passed all the unittest specifications in an oop lab. but they told me that I failed a hidden test. that my code can still be improved upon. I've tried my best but I don't know how to improve the code again. please give me ideas. am I using WET in any block. any unnecessary repetitions or redundancy? this is the code below:
http://www.sololearn.com/app/python/playground/cG5UEvIEkuHd/
0 Votes
4 AnswersHi, I need assistance aka HELP!
I've done this calculation in various ways some of printed nothing but zeros non stop.
Using while loop calculate all numbers 1 to 1000 add numbers to sum = sum + i
int sum = 0;
// use a while loop to calculate the sum of 1 to 1000
While(int sum = 0; sum >= 1000; sum = sum + I){
System.out.println(sum);
}
0 Votes
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