Q&A Discussions
l want to program code that compare two values x and y , return 1 if x is greater than y else return 0 if x is equal to y or else return -1 if x less than y . Then program must accept user input
0 Votes
6 Answers
def aunt(x, y):
return x + 2
def log (x,y):
return x*y
def do_twice(name, x, y):
return name(name(x, y), log(x, y))
x = 5
y= 3
print(do_twice(aunt, x, y))
Solve this problem step by step
0 Votes
3 Answers
Hi guys.... What am I missing on my code.i want to return 1 if all the numbers are divisible by two and return 0 if not all
1 Vote
7 Answers
Returning from functions
-1 Vote
4 Answers
include <stdio.h>
int main() {
int b=7,a;
a=b++ + ++b+b++ ;
printf ("%d\n",a);
return 0;
}
2 Votes
7 Answers
#include <iostream>
using namespace std;
int main() {
int a=10,b;
b=++a+(++a);
cout<<b;
return 0;
}
5 Votes
9 Answers
I tried this code:
def multiply_numbers(x, y):
if x>y:
return x
else:
return x*y
print(multiply_numbers(4, 5))
It says syntax error on line 4. Can someone please help out?
1 Vote
7 Answers
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