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In the continue Loop -
i = 0
while True:
i = i +1
if i == 2:
print("Skipping 2")
continue
if i == 5:
print("Breaking")
break
print(i)
print("Finished")
It shows the output being
"1
Skipping 2
3
4
Breaking
Finished"
Why are the last three lines not
"Breaking
5
Finished"
Where it shows print(i) after break?
1 Vote
3 Answerscan someone please explain why this code keeps telling me complication error instead of outputting the value of speed.
#include <iostream>
using namespace std;
class myClass {
public:
void setcarspeed (int a){
speed=a;
}
int getcarspeed(){
return speed;
}
private:
int speed;
};
int main() {
myClass obj;
obj.setcarspeed (40);
cout<<obj.getcarspeed ;
return 0;
}
2 Votes
3 Answersis the javascript used for server side same as that of client side javascript??
i mean is syntax exactly same.
i want to know difference. there must be some.
i know node.js is used in backend and jquery,angular in front end, but overall they r javascript so why should it matter???.
thanks in advance
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