Q&A Discussions
While runing the code kotlin in my phone i can not enter more than one input. So i can't run a code with more than one input
0 Votes
2 Answers
How to make for loop fast?
2 Votes
7 Answers
Create a for loop that iterates up to 50 while outputting "hello" at multiples of 4, "world" at multiples of 6 and "hello world"
0 Votes
1 Answer
Using a while loop write a java program that will prompt a user to enter two integers using a keyboard and return their sum.
0 Votes
2 Answers
Help with simple "ATM" code
0 Votes
2 Answers
How can I fix this?
0 Votes
2 Answers
In C++ I want to take input 1 for even number output and input 2 for odd number output. How I limit input to user.
0 Votes
4 Answers
Why its shows error while try to pass the value as normal interger a and b into the function update instead of passing ptr var?
0 Votes
1 Answer
Scopes In Java
0 Votes
8 Answers
Everybody know while scrapping with php i get a error failed to open stream php_network_getadresses: no such host is know n
0 Votes
1 Answer
It has been a while but can Java not store integers of 8-bit in a char like C and C++ ?
-1 Vote
1 Answer
What the difference between :
-2 Votes
3 AnswersWhat is the value of h(6,8) for the function below?def h(m,n): ans = 1 while (n > 0): (ans,n) = (ans*m,n-2) return(ans)
0 Votes
2 Answers
#include <iostream>
using namespace std;
int main()
{
int num = 1;
int number;
int total = 0;
while (num <= 5)
0 Votes
2 Answers
Text Editor Help!?!
1 Vote
7 Answers
There is a wrong answer.
-1 Vote
2 Answers
3x+1 conjecture
0 Votes
2 Answers
sentence=input("Enter a sentence:")
Can someone Just point out to me why it's showing syntax error in this particular line??? it's showing SyntaxError- Unexpected EOF while parsing
0 Votes
3 Answers
When someone calls you over nd over again while your doing a challenge! 😠🔫 Anyone else have had this happend to them?
0 Votes
1 Answer
I want print just the odd lines from text how can I do that?
I wrote this code but it print just the first line
f=open('12.txt',r)
n=0
while True:
if n<=6:
n=n+1
if n%2==1:
lines=f.readlines ( )[n]
print lines
else:
break
0 Votes
8 Answers
Kotlin infinite loop
1 Vote
1 Answer
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