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def add(x, y):
return x + y
def do_twice(func, x, y):
return func(func(x, y), func(x, y))
a = 5
b = 10
print(do_twice(add, a, b))
Please explain step by step
Which is caller here?
Explain the 3rd and 4th line ?
why in 4th line we write add(add(x,y),add(x,y)) which is function of 1st line ?
how can we write function after return statement insted of (x+y+x+y )=30?
0 Votes
2 Answerswhy we write return 0; ????
0 Votes
2 AnswersWhat is return 0 ?
0 Votes
4 Answers
what have i to do, if i want that the program always writes for example :
0+1
1+2
3+3
6+4
10+5
15+6
...
because now it just writes
1
3
6
10
15
...
and maybe if it works, can i make then
0+1=1
1+2=3
3+3=6
6+4=10
#include <iostream>
using namespace std;
int main(){
int i;
int sum = 0;
for (i = 1; i <= 100; i++){
sum = sum+i;
cout<<sum<<endl;
}
cout<<sum;
return 0;
}
1 Vote
5 Answersif i text 21 it stacks. program says you are a child. you are a teenager. you are adult. how can i delete this "stack".
#include <iostream>
using namespace std;
int main() {
int age;
cin>>age;
if (age>=14){
cout<<"You're a Teenager"<<endl;
}
if (age>=18){
cout<<"You're adult"<<endl;
}
if (age>=0){
cout<<"You're a Child"<<endl;
}
else{
cout<<"Are u stupid ?"<<endl;
}
return 0;
}
0 Votes
4 AnswersWhat is the output and why?
public static int[] make (int n){
int[]a=new int [n];
a [i]=i+1;
}
return a;
}
public static void dub (int []jub){
for (intent i=0;i <jub.length;i++){
jub*=2;
}
}
public static int mus (int []zoo){
int jus=0;
for (int i=0;i <zoo.length;i++){
jus+=zoo [i];
}
return jus;
}
public static void main (String [] args){
int [] bob =make(5);
dub (bob);
System.out.println (mus (bob));
}
0 Votes
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