Int x=035; int y=014; int c =a+b; what is the value of c

Answer 1

/* here are some special notations for specifying the base*/
//might error will come bcz it will convert it to octal from decimal and int datatype will not be able to hold that large number

https://code.sololearn.com/cFhPmtl1XAfT/?ref=app

one more thing , u by mistakely wrote a,b in place of x,y & Int in place of int
*/

https://stackoverflow.com/questions/23039871/why-int-j-012-giving-output-10

Answer 2

sorry in place of 038 use 035 mistake in writing

Answer 3

emm, what? its joke ?

Answer 4

no it's not a joke

Answer 5

answer is 41

Answer 6

okey, why x,y initialized from zero (038, 014) why a and b are not declared, and what means " what is the value of c" it's looks likr trolling, if you try compile it you get error...

Answer 7

0 is used before number because of 0 is used to represent the Octal number

Answer 8

Now i know about octal numbers...
https://code.sololearn.com/cjIu9Fg5MwKG/?ref=app
ps: correct the post, not c= a + b. c=x+y