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Floating point exception
if "num" is any 5 digit integer number "sum" is in integer. then sum =0; for(int i=1;i<=5;i++) { sum = sum + num%pow(10,i); num = num/10; } I'm getting Run time error i.e., "floating point exception" Please explain me the reason.
3 Answers
0
Yes.I was trying to reverse the number..
I did it with 3 statements in loop..But I was just trying it too and thought it'll work..
I'll try your method too..
Thank You