Code

Question

What is the result of this code?
if not True:
print("1")
elif not (1 + 1 == 3):
print("2")
else:
print("3")

please explain why 2

Answer 1

"1" will not be printed because the condition of the first " if " statement is false:
(not True) => False

"2" is printed because the condition of the second " if "is true:

(1+1 == 3) => ( 2 == 3 ) => False
and
not (1 + 1 == 3) => not False => True