+ 2
What is Output of this code...?
#include<stdio.h> int main() { printf("%c\\n", ~('C' * -1)); return 0; }
2 Answers
+ 5
run the code on the "C" code playground
+ 2
B\n
Youâre using double \\ so \n wonât be interpreted as newline!
#include<stdio.h> int main() { printf("%c\\n", ~('C' * -1)); return 0; }