How does python do this?

Question

https://code.sololearn.com/cJ352C6ojsoS/?ref=app

Answer 1

When the list x is created it had eight items
[0, 1, 2, 3, 4, 5, 6, 7]

The first time through the for loop i is the first item in the list or 0.
The 0 is removed from the list which becomes
[1, 2, 3, 4, 5, 6, 7]

The second time the for loop sets i to the second item in the list which is now 2 not the original 1.
The 2 is removed and the list is now
[1, 3, 4, 5, 6, 7]

The third time though the for loop i becomes the third item in the list 4. The 4 is removed and the list is now
[1, 3, 5, 6, 7]

The fourth time through the for loop i becomes the fourth item in the list 6. The 6 is removed and the list becomes
[1, 3, 5, 7]

There is no fifth item in the list now so the for loop ends.

Answer 2

x.remove(i) removes the item i from the list not the item at index i. If you have a list x = [1,2,3,4,5,6,7]
x.remove(1) will remove the 1 at index 0 from the list, not the 2 from x[1].

Answer 3

To understand better print(i) and print(x) inside the loop you will get to know each and every step in the process.

Answer 4

You're right Joseph Whalen ... SORRY!