How do I use input? (read description)

Question

If I put something like this:

iiS = input()
if iiS == ['3', '4', '5']
print('HelpMe')

if iiS == ['6', '9', '11']
print('Please')

It says "No Output" when there should be if the user inputted 3, 4, 5, 6, 9, or 11, right? Can someone help me?

Answer 1

You are trying to compare the variable to the whole tuple or set, instead of checking if the input is in the set.
Your if statement should use the syntax of:
if iiS in ('2', '3', '4'):
...

Answer 2

If I put something like this:

iiS = input()

if iiS == ['2', '3', '4']:
print('A')

if iiS == ['18', '19', '20']:
print('B')

It doesnt print anything when i input anything on the two lists.

If I do this:

iiS = input()

if iiS == ('2', '3' ,'4'):
print('A')

if iiS == ('18', '19', '20')

I get both A and B

What do I do?

Answer 3

iiS = input()

if iiS in ['2', '3', '4']:
print('A')

if iiS in ['18', '19', '20']:
print('B')

see the difference? this way checks if the number is IN the list you provide.

iiS in ..... this will check a list to see if I contains an item.

iiS == .... this will check for 1 specific item

iiS in [1,2,3]
iiS==1
iiS==2

This applies to both methods your trying to use

iiS = input()

if iiS in ('2', '3' ,'4'):
print('A')

if iiS in ('18', '19', '20'):
print('B')