Why is not printing names ??

Question

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// The student structure
union Student {
char* name ;
int roll_number;
float marks;
};

int main()
{
int i = 0, n = 5;

union Student student[n];

//Students data
student[0].name = "Kapil";
student[0].roll_number = 1;
student[0].marks = 73.6;

student[1].name = "Vikas";
student[1].roll_number = 2;
student[1].marks = 78.3;

student[2].name = "Ajay";
student[2].roll_number = 3;
student[2].marks = 87.4;

// Print the Students information
printf("Student Details:\n\n");
for (i = 0; i < n; i++) {
printf("\tName = %s\n", &student[i].name);
printf("\tRoll Number = %d\n", &student[i].roll_number);
printf("\tTotal Marks = %f\n\n", &student[i].marks);
}

return 0;
}

Answer 1

You can't use a union. Unions only allow for one attribute to be held at one time. You can't assign all three cause each assigment will overwrite the last.

Answer 2

Use struct instead of union.

And remove & in loop print statements..

printf("Student Details:\n\n");
for (i = 0; i < n; i++) {
printf("\tName = %s\n", student[i].name);
printf("\tRoll Number = %d\n", student[i].roll_number);
printf("\tTotal Marks = %f\n\n", student[i].marks);
}

since you added only 3 values, use n=3

Answer 3

Yes. Union only holds one last attribute value stored by overwriting..

Answer 4

Bro I want the using union

Answer 5

So what should I do to print the data of three students using unions