Why do I get "1" at the end?[SOLVED]

Question

This is a sololearn JS challenge question. Why does the console output 1 and and not 0?

code:
https://code.sololearn.com/cR31C1ODc66Z/?ref=app

Answer 1

ɴᴜʟʟ there post increments x++, I++ are independent tasks. So complete task is done there.
Those are single instructions. Have no compound operations. So after incrementing only goes to execute next instruction, first x++, then next i++

Ex: if you have statement like console.log(x++) ;
Here, it's a compound statement of having console.log for printing x and x++ so it first prints x value and then increments x value.
Ex2:
x=1
x++ + ++x, (1+3=4)
operations done like
x(using value first) ,
then x++, (x value updated to 2) ,
now ++x, (x value updated to 3)
so finally 1+3=4

Hope it helps..

Answer 2

Why you expect 0 ?
Do you don't want loop to run? write your understandings..

Your loop runs and first iteration I=0, x incremented x++ and you have break statement immediately so loop exits. And x=1 , it's printed.
If you don't have break then x=5
If you don't run or have loop then x=0

Answer 3

Because you incremented x for once before breaking the loop.

Answer 4

ɴᴜʟʟ , it's completely normal. In the loop x is incremented once, then you break the loop and the variable is now 1.

Answer 5

zexu knub , TheWh¡teCat 🇧🇬 and Jayakrishna🇮🇳 ,
Sorry, I should have mentioned my understanding.
x++, here it (++) is a postfix operator means it should increment after the task is done. So, on the first iteration shouldn't the x value be 0? And on second iteration 1 as incremented after operation. But as loop breaks it doesn't move on to second iteration and x remains 0.

Answer 6

Jayakrishna🇮🇳 Yes, now I have understood thank you very much.
In the loop x has incremented after the iteration. Means on printing the x with console.log() the incremented value is being printed.