Answer 1

#include <iostream>
#include <typeinfo>
#include <cxxabi.h>
using namespace std;

int main() {
unsigned a = 1; // default unsigned int
int unsigned b = 2;
unsigned int c = 3;
int d = 4;
unsigned char e = 'e';
cout << abi::__cxa_demangle(typeid(a).name(),0,0,0) << endl;
cout << abi::__cxa_demangle(typeid(b).name(),0,0,0) << endl;
cout << abi::__cxa_demangle(typeid(c).name(),0,0,0) << endl;
cout << abi::__cxa_demangle(typeid(d).name(),0,0,0) << endl;
cout << abi::__cxa_demangle(typeid(e).name(),0,0,0) << endl;
return 0;
}

/*
unsigned int
unsigned int
unsigned int
int
unsigned char
*/

Answer 2

No difference. The ’unsigned a’ is a shorthand for ’unsigned int a’.

unsigned a
unsigned int b
typeof(a) === typeof(b) // true

In general unsigned can be used as a qualifier for other integral types but defaults to an int.

~~~

Just for reference as a reminder; a difference between a signed and an unsigned int is that the former can have negative values and the later only positive values.

Answer 3

"unsigned" is a type modifier for *int* data type, and you may omit *int* keyword if you use any of its modifier.

So like Kilian Lindberg said, both "unsigned" and "unsigned int" would be interpreted as basic integer type with unsigned modifier.

Check cppreference to learn more about fundamental types on C++ 👇
https://en.cppreference.com/w/cpp/language/types

Answer 4

idk what to say about c++

Answer 5

The code above outputs the actual type of variables, and then you'll see their difference.

Answer 6

signed int = can have positive as well as negative values.
Unsigned int = can only hold positive values.

{Remember like this :-
Signed int :- +ve sign, -ve sign.
Unsigned int :- only holds positive.}

Answer 7

#include<iostream>
using namespace std;
int main(){
//Subtraction of two numbers.

Signed int a ; // eg. -3, 4, 8, -6.

Signed int b; // eg. same.
cout<<"Enter the first number:";
cin>>a;

cout<<"Enter the second number:";
cin>>b;

Signed int result = a-b;
cout<<result<<endl;

return 0;
}