Pointer++ in c, weird part for me, why?

Question

I do code challenge and get confused, please tell me if you know why it act like this. Below is the question:
What is the output of this code?
int x = 4;
int *p = &x;
int *k = p++;
int r = p - k;
printf("%d", r);

The answer is 1, and I don’k know why k’s value is 1 int size before p, suppose if they are int variable(that is int p = x, int k = p++), then the value of p and k are the same,
But why does this not work the same rule in pointer++ and assignment, sorry for my bad English, and thank you

Answer 1

<p> is post-incremented here

int* k = p++;

So <k> gets a copy of address stored in <p> before <p> was incremented.

Is this what you asked for?

Answer 2

P is and address to x, k is the same address locations plus 1, therefore 1 minus the original address is 1 which is r.

I see what you are saying now it should be -1 not 1.

Answer 3

int x = 4;
int *p = &x;
int *k = p++; // p is post incremented
printf("%p %p", &x, k); // <= same address

Answer 4

William Owens Ok, i see now, you are right, thanks 🙂
Ipang thanks bro, i know what’s going on now 🙂
rodwynnejones yup, you are right, thanks 🙂

Answer 5

No, in your opinion, p - k will be -1, run the code then print the address of them, then you will know that k is address of p minus 1, that’s why the weird part and i don’k know why…🥲