What is the problem

Question

GNU nano 6.0 ch.c
#include <stdio.h>

int main() {

char *arg[] = {"One", "Two", "Three"};
char ** argg;

argg = &arg;

printf("\n%s\n", **argg[0]);

argg++;

printf("\n%s\n", **argg[0]);

return 0;

}

Answer 1

ChingBling it looks like all your references and de-references are one or two levels too deep. Back out of all levels and it works:

argg = arg;

printf("\n%s\n", argg[0]);

argg++;

printf("\n%s\n", argg[0]);

Output:

One

Two

Answer 2

Thanks for the help