Find lowest number in a list

Question

Write a function which accepts an input list of numbers and returns the smallest number in the list (Do not use python's built-in min() function).

If I use print function m_num = x(0) to get lowest number it is not working. Please Help!!!

sample_list = [5,6,7,1,0,2]
def min_num(x):
e = []
m_num= x[0]
for i in x:
if i<m_num:
e.append(i)
return e
print(min_num(sample_list))

Answer 1

Sorting isn't necessary.

sample_list = [5,6,7,1,0,2]
def min_num(x):
min = x[0]
for i in range(1,len(x)):
if x[i] < min:
min = x[i]
return min
print(min_num(sample_list))

Answer 2

print(sorted((map(lambda x: int(x),input().split(','))))[0])
just enter numbers separated by comma
input: 12,5,46,7,0

Answer 3

def min_num( lst ):
lst.sort() # sort it first,
return lst[ 0 ] # then return the first element

You said "returns the smallest number in the list ..." why you returned a new `list` <e>?

Answer 4

Thank you!! It took me great amount of hours to figure out..failed then asked question!! Thank you for your continued support!!👍