How do i write the try and except of this?

Question

The input should be a number (ie not alphabets or dots and other stuff) and only between 10-20, Inputs above 20 or below 10 should also be in the except part(i think)
z = x <=20 and x >= 10 #this is the condition
print(”write a number”)
x = int(input())
Try:
x=int(input())#i dont know if i should add the conditions within this part or not and how
Except:
print(”wrong input”)#can i specify what kind of wrong input they gave etc?

Answer 1

try:
n = int(input("enter a number bt 10 and 20"))
assert 10 <= n <= 20
except:
print("not allowed")

Answer 2

Oma Falk Why is there a bare except statement? It should be : except ValueError

Answer 3

Gurseerit Singh Chahal You are absolutely right as well as Nboumakis

Answer 4

As a sidenote, you shouldn't rely on try-except structures for flow control and that includes using assertions to check whether the value is in a specific range. It makes your code hard to read and unpredictable for the next person to read it. Use an if statement instead.

ALWAYS try to write clean, consistent and self-documenting code, and avoid "cool" or "clever" code, unless absolutely necessary. It makes everyone's job easier.

Edit: My point is mostly made for professional environments or for code that has the possibility of being used for more than fun or more than once

Answer 5

Gurseerit Singh Chahal like this?:
except ValueError :
print(”Numbers only!”)