+ 1
any help with the SQL zoo code project on this app?
2 Answers
+ 3
-- 28 Code project "Giraffe"
insert into Animals -- (name, type, country_id)
values ('Slim', 'Giraffe', 1);
select a.name, a.type, c.country
from Animals a
inner join Countries c on c.id=a.country_id
order by c.country;
+ 2
Hey Kofi Moore,
Many had attempted to solve it and asked questions around it. May I suggest you to search the forum first? surely you can have clues and guidance from previous discussions on this topic š