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Can someone help me to understand this code â ?
// Why this output ?? #include <stdio.h> #include<stdlib.h> int main (){ unsigned char x =300; printf("%d",x); return 0; } //Output : 44
11 Answers
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FF9900 it just output 44 is for what i hoped to show 300
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44
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It given the overflow number instend of the rest
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Where going the 256 bits rest so
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Mik_RDC
unsigned char is from 0 to 255.
Go over that and it starts from 0 again. so 256 = 0, 257=1... 300=44.
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You declared a char type but assigned it an int type... Therefore unsigned conversion of int to unsigned conversion to char outputs a number your case 44