Question on C++ for loops 👇🏼👇🏼👇🏼

Question

What's the code for printing this format
👇🏼:
1
2 3
3 4 5
4 5 6 7
5 6 7 8 9

Answer 1

Solved

https://code.sololearn.com/cIyxuNaa7Ze9/?ref=app

Answer 2

What have tried so far.. ?

Your try is first..

Use 2 loops, first outer loop tells how many to print from
2 nd loop does the job,

For I =1 to n
For j=I, print j succesive numbers from j. jump to next line..... as simple as that,.

Answer 3

Jayakrishna🇮🇳
I tried this one
for (int t = 1; j <= 5; t++)
{
for (int r = t; r <= 5; r++)
{
cout << r;
}
cout << endl;
}

But it gives me this 👇🏼
12345
2345
345
45
5

Answer 4

Just modify condition r<=5 to r < t+t

1st condition had typo, that you are using j instead of t. add space if you want cout<<r<<' ';
look good everything 👍

Answer 5

Alvin✓

Look again

// variable row is for tracking the row

// variable col is for tracking the column

// just look carefully each row is starting with the number equal to its row number. for example row 1 is starting with number 1. Row 2 is starting with number 2 and so on...

// and also note that each row is printing numbers equal to its row number. for example...

// row 1st is printing only 1 number

// row 2nd is printing only 2 numbers (2, 3)

// row 3rd is printing only 3 num (3, 4, 5)

// so it means, each row is printing numbers upto one less than twice of row number or simply less that twice of (2*row)

// twice of 1st row is 2
// so 1st row has number < 2 (upto 1)

// sumilarly, twice of 2 row is 4
// so 2nd row has number < 4 (upto 3)

// twice of 3rd row is 6
// so 3rd row has numbers < 6 (upto 5)

// similarly twice of 5th row is 10
// so 5th row has numbers < 10 (upto 9)

Answer 6

NonStop CODING can you explain the code please?

Answer 7

#include <iostream>
using namespace std;

class Add {
public:
int i,j;
};

int main() {
Add obj;
for(obj.i=1; obj.i<=5; obj.i++)
{
for(obj.j=5; obj.j>=obj.i; obj.j--)
{
cout<<obj.j;
}
cout<<endl;
}
return 0;
}

Out Put this program
54321
5432
543
54
5

Like and. Follow

Answer 8

Why