Bug in reverse alphabet code

Question

The code works in general except when a letter replaced by a letter and then followed by the same letter. Then it "skips" that letter. I don't understand where the problem is.

For example input "piz" outputs "kra" which is correct. But input "pizza" outputs "krzzz" which is wrong.

dict = {"a": "z", "b": "y", "c": "x", "d": "w", "e": "v", "f": "u", "g": "t", "h": "s", "i": "r", "j": "q", "k": "p", "l": "o", "m": "n", "n": "m", "o": "l", "p": "k", "q": "j", "r": "i", "s": "h", "t": "g", "u": "f", "v": "e", "w": "d", "x": "c", "y": "b", "z": "a"}

x = input()

for i in x:
x = x.replace(i, dict.get(i))

print(x),

Answer 1

I came up with this alternative solution :)

x = input().lower()
result = ""

alph = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]
revalph = alph[::-1]

for i in x:
    if i in alph:
        ind = alph.index(i)
        result += revalph[ind]
    else:
        result += i

print(result)

Answer 2

alph = list(map(chr, range(ord('a'), ord('z')+1))) # Alphabet a to z

Answer 3

Wow so you typed all the keys and values 😊
Thats a lot of work, find a work around

Back to the question
Okay so the thing is replace replaces all the duplicates

So what you need to do is, pass the second parameter of replace so

In general the syntax of replace is

.replace(new, old, count)

So you can specify a count which is, 1 in your case to affect just one character

Answer 4

Okay thats a bit okay