Why I'm getting garbage value..??? what's wrong with this code😓..... Answer should be..... index = [ 0, 3]

Question

https://code.sololearn.com/cIS8dwVxquqU/?ref=app

Answer 1

Davinder Kumar

You are printing array 'result' which is giving address of 'result' array not garbage value.

print this:

System.out.println(result[0]);
System.out.println(result[1]);

or you can print like this:

System.out.println(Arrays.toString(result));

note : import - Arrays class

Answer 2

Davinder Kumar

You have assigned array not value and when you print array or object it's print address (which is not a garbage value) not value.

If you want value then print like that as I replied previously.

Answer 3

Davinder Kumar

One more thing 7 exist at position 1 and 2 then how your output should be [0, 3]?

Here is solution of your "Garbage value" as you said:

https://code.sololearn.com/c88IY4U25LIu/?ref=app

Answer 4

Davinder Kumar

That's your logic problem. I just given answer on your Garbage value question.

You have to check your logic again.

Answer 5

Davinder Kumar

Again I am telling that's not the problem of that value.

If you want to see actual result then print this:

Arrays.toString(result)

Instead of result

Remember you have to import Arrays class before printing Arrays.toString(result)

import java.util.Arrays;

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Note: just search on Google why result comes like that when you print array object.

Answer 6

no you didn't get my point anyway thanks for giving your precious time....!

Answer 7

Davinder Kumar

I got your point but I think you didn't get what I said even I also explained what is right and what is wrong.

Answer 8

look i have assigned function's value in result just to print the final result. still don't get why I'm getting such output 😓

Answer 9

no that's wrong answer

Answer 10

answer should be index = [ 0 , 3 ]

Answer 11

My Logic is completely right i believe... there might be something due to which it throws such value